SECTION VI

 

 

 

NATURAL GENETIC ENGINEERING:

GENE TRANSFER AND RECOMBINATION IN BACTERIA

 

 

A. Background Material on Natural Genetic Engineering:

Conjugation, Transduction. Transformation ……………………….…2

B. Experimental Protocol for Conjugation………………………………..5

Procedure

Alternative Procedures

For Thought and Discussion

C. Natural Genetic Engineering in the Real World………………………10

Isolation Experiment

Conjugation Experiment

Comments and Questions

D. Optional Experimentation

Transduction…………………………………………………………16

Transformation………………………………………………………27

 

 

 

 

 

A. BACKGROUND MATERIAL ON NATURAL GENETIC ENGINEERING

Conjugation

Although bacteria have been an object of study for several hundred years, for most of that time scientists did not consider bacteria "real" cells. Since there was no observable nucleus, so the accepted wisdom dictated, there could be no inheritance. This view was dispelled in the early 1940's, due in large part to work done by Joshua Lederberg and his colleagues at UW-Madison, who demonstrated recombination in bacteria. In doing this, they also discovered natural intraspecies gene transfer by a process later called conjugation (which, effectively, showed that bacteria have sex!).

Certain strains of E. coli were found to exhibit non-genomic inheritance: genes which do not necessarily reside on the bacterial chromosome, but on autonomously replicating chromosomes (that can "jump" to and from the bacterial chromosome). Later, it was shown that bacteria can indeed contain, besides genomic DNA, what was called a plasmid DNA molecule. This small, circular DNA can replicate autonomously in the cell (so-called F+ cells), or can integrate into the host cell chromosome (cells containing this "episome" in their chromosome are called Hfr cells, as discussed below).

The plasmid contains several genes which confers fertility on the host cell: i.e. fibrous proteins which form pili, allowing cell-cell contact (with so-called F- cells), and other genes which mediate transfer of F DNA to a recipient (F-) cell. That is, it has the ability to copy its DNA and transfer it to the F- cell through the cytoplasmic bridge. On rare occasions, the F DNA is integrated in the host chromosome. The cell is then called an "Hfr" cell, for "High frequency of recombination". An Hfr strain can also transfer copies of host chromosomal genes to an F- cell along with the F DNA.

The transfer of host chromosomal genes occurs in a fixed order from the point of origin, the site at which F is integrated into the host chromosome. The strain is then a "merodiploid" for the resulting duplicated sequence; subsequently, homologous regions of the chromosomes can undergo recombination, conferring on the resultant cell, a different genotype. It would take about 100 minutes to copy and transfer the 4000 genes from the Hfr to the F-. If ‘mating’ is disrupted during that transfer, only the genes closest to the first F factor block of genes will be donated. The gene farthest away on the circular DNA seldom gets transferred. This system was used to provide the first genetic map of E. coli.

Some strains of E. coli have genes that confer resistance to antibiotics. Some of these genes reside in chromosomal DNA; the majority are on plasmids (called "R plasmids" for "resistance"). Examples are strains with chromosomal genes for tetracycline resistance (tetr ) or for streptomycin (strr). A bacterium with a tetr gene, for example, would grow on media with tetracycline in it, which would otherwise be lethal for the bacterium.

Transduction

Early in the infection of a bacterial cell by a virulent bacteriophage, phage genes are expressed that code for nucleases that specifically chop the host DNA into pieces. Later in the infection, phage genes are expressed that code for proteins that package the newly made phage DNA into also newly synthesized phage coat protein. For some phage, the size of the host DNA fragments is roughly the same as the size of the phage genome, and host DNA---rather than phage DNA---can, on occasion, become packaged inside the phage coat protein. The result is a phage particle that behaves as kind of a "Trojan horse": it can attach to another bacterium, but instead of injecting phage DNA, a fragment of the (now) dead bacterial host DNA is injected. This DNA will inevitably be homologous to a region of the newly infected host (since the usual situation would involve the same species and---under laboratory condition, the same strain) , thereby setting up a condition in which recombination can occur. If the injected DNA carries a gene that is allelic to the new host DNA, a recombination would produce a new genotype and a selectable new phenotype.

 

Transformation

One of the first demonstrations that DNA is the genetic material was the isolation of DNA from one strain of Diplococcus pneumonia (aka: pneumococcus) and its use to cause heritable changes in recipient strains of pneumococcus. This phenomenon is known as transformation and involves the uptake of naked DNA with subsequent recombination of homologous regions of the donor and receipient chromosomes. (N.B. This is referred to as "genomic" transformation, to distinguish it from transformation brought about by the uptake and expression of plasmid DNA. The latter does not require recombination; it will be dealt with in a later section.)

Not all bacteria demonstrate this phenomenon (or at least under the laboratory conditions so far used to study this phenomenon). The two other bacteria in which this has been studied are Bacillus subtilis and Hemophilus influenzae. In all three cases, it was found that cultures of cells are "competent" to undergo transformation only under special growth conditions, suggesting that preparing cells to take up DNA and undergo recombination is triggered by diffusable factors in the medium by mechanisms that are still not at all clear.

Apart from the intrinsic interest in the process of transformation, it served as a very useful research tool in the early days of molecular biology since it provided the only way to correlate physical and chemical alterations of DNA with observable effects on expression of genetic information. You are encouraged to read the material at the end of the syllabus taken from Malacinski and Freifelder on conjugation, transduction, and transformation. At the end of this section are descriptions and protocols for transduction and tranformation experimentation should you wish to work with this during the course.

 

B. EXPERIMENTAL PROTOCOL FOR CONJUGATION

In this exercise, the antibiotics tetracycline and streptomycin will be used to select bacteria with DNA for resistance to both. (Tetracycline is used to treat penicillin resistant strains of gonorrhea and streptomycin is used to treat acne and boils. Indiscriminate use of antibiotics will select for strains resistant to the antibiotics.) The Hfr strain (Hfr Cavelli or HfrC) used in this investigation has a transposon , called Tn10, inserted into the chromosomal DNA (at position 1'). This transposon has the gene for tetracycline resistance. The genotype is therefore: Hfr tetrstrs; phenotypically, it will grow in medium containing tetracycline but not containing streptomycin. The F- strain (AB1157) has no insert, so it has no tetracycline resistance, but is sensitive to the drug. However, it has a gene for streptomycin resistance at another locus, corresponding to the recessive strs allele on HfrC. The genotype is therefore: F- tetsstrr; phenotypically, it will grow in medium containing streptomycin but not containing tetracycline.

During conjugation, some recipient cells will receive DNA containing the tetrgene; subsequent recombination will create, among other possibilities, cells carrying both the tetr allele and the strr allele. These recombinants can be selected for by plating the cell mixture on medium containing both antibiotics.

MATERIALS

Overnight cultures of Hfr strain and F- (AB1157) strains

L broth

Sterile flasks

Plates: L, L+strep, L+tet, L+strep+tet

sterile tubes, pipets, tips.

marker

burner and loop

PROCEDURE

1. Subculture overnight Hfr and F- cultures by diluting them 1:25 in fresh L broth; grow both at 37oC with shaking to 3-8 x 108 cells/ml (OD550 ≈ 0.3-0.5; ca. 3 hrs)

2. When the cultures have attained the desired cell density:

a. Mix 0.2ml Hfr + 0.2ml F- in large sterile test tube;

---let tube sit 90min, 37oC;

---add 2ml L broth and grow in 37oC shaking water bath 1-2 hr;

---then plate 0.1ml of a 102, 103, and 104 dilutions of this culture on LB+strep+tet plates, and plate 0.1 ml of 105 and 106 dilutions on L agar plates, L+tet plates, and L+strep plates (these are the controls).

b. Mix 0.2 ml Hfr + 0.2ml L broth in large sterile test tube and let it sit 90 min., 37oC: ---add 2 ml L broth and grow at 37oC in shaking water bath;

---plate 0.1ml of a 101 dilution on L agar +strep+tet only.

c. Mix 0.2 ml F- + 0.2ml L broth in large sterile test tube and let it sit 90 min., 37oC; ---add 2 ml L broth and grow at 37oC in shaking water bath;

---plate 0.1ml of a 101 dilution on L agar+strep+tet only.

(d. Optional: plate 0.1 ml of a 106 dilution of F- culture on L agar +strep to calculate

efficiency of conjugation.)

4. Incubate all plates overnight at 37oC. Record your expected results.

5. Count plates the next day; record the plate counts and determine the titer for each sample.

titer = (plate counts) x (dilution factor)

volume plated

 

TITER

MEDIA Hfr F- Hfr+F-

L agar alone ___ ___ ___

L agar with tetracycline ___ ___ ___

L agar with streptomycin ___ ___ ___

L agar with tetracycline and streptomycin ___ ___ ___

 

NOTES:

1. It would cut down on prep time for a class if you were able to use on overnight culture without the 3 hr growth period. But how do you know that conjugation might be strongly favored--or even dependent on--a culture in exponential growth?

2. Try testing out the mechanical strength of the conjugation bridge by shaking with different degrees of vigor during the conjugation period (Hint: the famous 'interrupted mating" experiments that permitted creation of the first genetic map of E. coli was accomplished with the use of a Waring blender!)

ALTERNATIVE PROCEDURES

1. Using an inoculating loop and cultures of HfrC and AB1157, streak a set of four plates as in the diagram below on L agar.

2. Incubate the plates overnight at 37oC or for 1-2 days at room temperature.

From this L agar plate, streak an inoculum from the mixed sector (bottom triangle) onto L, L + strep, L + tet, and L + tet + strep. (Alternatively, you could replica plate the L agar plate onto these three plates.) Incubate the plates overnight at 37oC. Indicate below your predictions regarding growth on the three plates, then the observed results. Explain the rationale of this procedure and the results.

 

Expected results:

Review the predictions you made on the table above, then draw in the growth pattern you predict on each plate:

L agar L agar+strep

L agar+tet L agar+tet+strep

Draw in the locations and concentrations of colonies you expect to grow on

each plate.

FOR THOUGHT AND DISCUSSION

A ‘gene map’ of a bacterial chromosome looks something like this:

Some of the recombinant progeny resulting from conjugation of the above bacterium with an F- strain would have some of these gene markers: some with C; less with C and A; less still with C, A, and D; and the least with C, A, D, and B. The decreasing number simply reflects the increased chance that the conjugation bridge will break with time and therefore preventing the transfer of genes further from the starting point. Using this knowledge, we have a tool for determining the location of genes on chromosomes, thereby making a gene map. For instance, if we found the resistance to the antibiotic streptomycin occurred when markers C, A, and D were transferred, or when all were transferred, but not when only C and A were transferred, we might reasonably infer the position of the streptomycin resistance gene to be somewhere between A and D.

Some F- bacteria lack the ability to biosynthesize the necessary amino acids threonine (thr), leucine (leu), proline (pro), and histidine (his). If the Hfr strain has the ability to produce all these, describe how this tool of using conjugation to produce recombinants could be used to determine the relative locations of the genes for amino acid biosynthesis. Which results would predict an order of leu -- pro -- his -- thr -- arg ?

C. NATURAL GENETIC ENGINEERING IN THE REAL WORLD:

CONJUGATION, ANTIBIOTIC RESISTANCE, AND WATER

(An activity based on a protocol designed by Dr. Susan West, UW-Madison School of Veterinary Medicine)

OBJECTIVES

1. To become aware of the spread of antibiotic resistant bacteria in our environment.

2. To study the relative ease for exchange of antibiotic resistant genes among bacteria.

INTRODUCTION

The spread of antibiotic resistance among pathogenic bacteria has become a significant public health problem with the past few decades. This was observed clinically and epidemiologically by physicians and public health officials not too long after antibiotics became part of the arsenal used to treat bacterial infections; and researchers were able to isolate plasmids that contained multiple antibiotic resistant genes. As the use of antibiotics moved from the treatment of human disease to the treatment of diseases in animals, particularly farm animals, and to their prophylactic use among livestock, public health officials began to suspect that runoff from farms may contribute to release of antibiotic resistant bacteria in many streams and lakes. This protocol is designed to test the hypothesis that antibiotic resistant microorganisms can be isolated from local streams and lakes.

In May, 1994, a survey was conducted of the following locations: Lake Mendota at the Memorial Union, Lake Mendota in Middleton, Lake Wingra, Monona Bay, Lake Monona, and the stream next to the School of Veterinary Medicine on the UW campus. All samples were evaluated for the presence of ampicillin-resistant microorganisms. Even though coliform bacteria, an indicator of fecal contamination, were found at several sites, ampicilllin resistant organisms were found at only two sites: Lake Mendota in Middleton and the stream next to the SVM. This exercise is a follow-up on this initial study. In addition, this exercise will also test the hypothesis that antibiotic resistant genes can be transferred by conjugation from one species to another. To study this, a multi-drug resistant Salmonella anatum strain will be mated with an E. coli strain.

Genes encoding resistance to antimicrobial agents, or antibiotics, are often present on plasmids. Plasmids are autonomous, self-replicating genetic elements that usually are not essential for bacterial survival. Many plasmids are able to move from one bacterium to another by a process called conjugation, and are called mobile, self-transmissible, or conjugative plasmids. These plasmids carry a number of genes, designated tra genes, which encode proteins needed for the transfer or conjugation process. Some of the tra genes encode the proteins for the sex pilus. Because of the large number of genes required for conjugation, conjugative or self-transmissible plasmids are usually large, at least 25kbp in size. Some plasmids cannot transfer themselves but can be transferred by conjugation because they are mobilized by self-transmissible plasmids. Such plasmids are called mobilizable plasmids and are much smaller because only one or two genes (i.e. mob genes) are required to take advantage of the transfer machinery provided by a self-transmissible plasmid. Self-transmissible or mobilizable plasmids often acquire multiple antibiotic resistant genes, frequently by insertion of transposons carrying these genes into the plasmid. Bacterial containing such plasmids can then transmit these antibiotic resistance genes to other bacteria. This process happens readily in nature and it is in this way that antibiotic resistance is spread from a resistant organism to a sensitive one. In this exercise, you will determine the number of antibiotic resistant microorganism in the creek next to the SVM, based on sample taken at several locations along the creek.

RATIONALE

A frequent source of contamination of many lakes and streams is fecal material, either from humans or animals. For this experiment, you will also assess the level of fecal contamination by determining the number of coliform bacteria present in the water sample. The word, coliform, means having E.coli-like characteristics (e.g. a small gram-negative rod that can ferment the sugar, lactose, with production of acid and gas). E.coli and other members of the family, Enterobacteriaceae, can be detected easily using MacConkey agar plates: organisms that ferment lactose form pink colonies on these plates, while lactose non-fermenters are colorless. Organisms that ferment lactose include: E.coli, Klebsiella, Enterobacter (Salmonella is a non-lactose fermenting member of the family Enterobacteriaceae)

MacConkey agar is a selective and differential medium used for the isolation of gram-negative bacilli. MacConkey plates are selective in that the growth of gram-positive organisms is inhibited, because of the inclusion of crystal violet and bile salts in the medium. MacConkey are differential because they can distinguish between organisms that ferment lactose and those that do not ferment lactose. When lactose is fermented, acidic endproducts are produced; the dye, neutral red, is included in the MacConkey agar as a pH indicator to detect this acid production by lactose fermenters. Thus, lactose fermenters form pink colonies, while lactose non-fermenter colonies are colorless or beige. The typical colony morphology on MacConkey agar is as follows:

• E.coli: rose-red color surrounded by a zone of precipitated bile

• Enterobacter/Klebsiella: mucoid, pink color

• Proteus: colorless, inhibition of swarming

• Salmonella: colorless

• Shigella: colorless

• Pseudomonas: irregular, colorless to pink

• gram-positive bacteria: no growth or partial inhibition

PROTOCOL

In this lab, you will be

1. isolating antibiotic-resistant strains from nature, and

2. performing a conjugation.

Prep Materials

Phosphate-buffered saline

LB broth

LB agar

MacConkey Agar

Antibiotics (* => light sensitive)

Ampicillin (10 mg/ml in sterile distilled water)

Kanamycin (50 mg/ml in 1:1 100% ethanol: distilled water)

Rifampicin (50 mg/ml in 100% methanol)

Tetracycline (10 mg/ml in 1:1 ethanol: distilled water)

Bacterial strains (1-3 ml/team of an overnight culture):

E. coli ER1398 (Rifr @ 150m g/ml; SW cc box 1, slot 30)

Salmonella anatum E1 (=stall C6, Apr, Chlr. Cbr. Rifs, SW cc box 17, slot 7)

Materials per team

Day 1:

Sterile container with 6-8 ft. string attached (for collecting water samples)

Sterile test tube containing 9 ml buffered saline (for dilution of sample)

Plate spreader, alcohol and burner

1 ml pipet

plates: 2 each of MacConkey, LB, LB + amp, LB+tet, LBB+kan.

Day 2:

Inoculation loop

Test tube containing 1 m LB broth (creek organism)

3 tubes containing

1 ml E. coli Rifr

1 ml E.coli Rifr + 1 ml Salmonella donor

1 ml E.coli Rifr + 1 lm creek donor

Day 3:

2 x 1 ml pipets

plate spreader

plates: LB + amp, LB + tet, LB + rif (x2), MAC + rifLB + amp + rif, LB + tet + rif, MAC + amp + rif, MAC + tet + rif,

Preparation

1. Let T = number of teams + 5. Pour the following plates

2xT MAC

2xT MAC + 100 m g/ml RIf

1xT MAC + 100 m g/ml RIf + 50 m g/ml AMP

1xT MAC + 100 m g/ml RIf + 50 m g/ml AMP + 25 m g/ml TET

2xT LB

3xT LB + 50 m g/ml AMP

3xT LB + 25 m g/ml TET

2xT LB + 50 m g/ml KAN

2xT LB + 100 m g/ml RIF

1xT LB + 100 m g/ml RIF + 50 m g/ml AMP

1xT LB + 100 m g/ml RIF + 25 m g/ml TET

Cover RIF ant TET plates; dry overnihgt and store at 4oC.

2. From plates, inoculate overnight cultures of E. coli and Salmonella strains the day prior to the experiment. Grow enough to have, per team:

3 x 1ml per tube E.coli recipient

1 x 1 ml per tube Salmonella donor

For the creek organism, each team needs 1 tube containing 1 ml LB broth.

Procedure

ISOLATION

DAY 1

1. Each team will collect a water sample from the creek next to the SVM (see attached map): there are 10 sites, so a decision must be made on how to get samples from all 10 sites.

2. Collect the samples in sterile tubes, each with a long piece of string tied around it. For collection of the samples, please wear latex gloves. Remove the cap of the tube and carefully lower the tube into the creek. When the tube has filled with water, remove it from the creek and replace the lid. Be sure you do not contaminate the tube or the water sample during this process. Return to the lab.

3. Pipet 0.1 ml of the water sample onto each of the following plates and spread sample evenly over the plates:

• MacConkey agar

• LB agar

• LB agar containing 50΅g/ml of ampicillin

• LB agar containing 25΅g/ml of tetracycline

• LB agar containing 50΅g/ml of kanamycin

Incubate plates overnight at 37oC.

(Since there is a good chance that the creek is polluted, please wash your hands carefully before leaving the lab.)

DAY 2

1. Count the number of colonies on each of the plates. For the MacConkey plates, record the number of lactose fermenting (pink/red) colonies and the number of lactose non-fermenting colonies. Record in the attached table.

CONJUGATION

2. Each team will perform two conjugations: one with an antibiotic resistant organism from the creek and the other with a multi-drug resistant, Salmonella anatum.

3. We will arbitrarily designate the creek organism as F+ since we suspect that it contains a conjugative plasmid. This is the donor strain which will be donating antibiotic resistance genes to a sensitive E.coli strain. The E.coli recipient does not contain any plasmids and therefore is designated as F-. However, it is resistant to rifampicin. In these matings we are using resistance to rifampicin as a way of selecting for and distinguishing the recipient from the rifampicin sensitive donor strain.

4. With a loop, carefully scrape off one colony from either the ampicillin or tetracycline plate and inoculate a tube of L broth and a tube of L broth containing the rifampicin resistant E.coli recipient.

5. Each team will also be given a culture of Salmonella anatum. This organism is sensitive to rifampicin. Since it contains conjugative plasmids, it is designated, F+. You will also be given a 1 ml culture of the rifampicin resistant F- E.coli recipient. Inoculate the E.coli culture with a loopful of the Salmonella culture.

6. Incubate both tubes from step 4 and the mating mixture from step 5 overnight at 37oC.

DAY 3

1. Pipet 0.1ml of the mating mixture from the creek onto each of the following plates and spread out evenly:

• LB agar containing 50΅g/ml ampicillin

• LB agar containing 100΅g/ml rifampicin

• LB agar containing 50΅g/ml ampicillin + 100΅g/ml rifiampicin

2. Pipet 0.1ml of the Salmonella-E.coli mating mixture onto each of the following plates and spread out evenly:

• MacConkey agar containing 50΅g/ml ampicillin + 100΅g/ml rifampicin

• MacConkey agar containing 25 ΅g/ml tetracycline + 100΅g/ml rifampicin

3. Streak the E.coli recipient onto the following plates:

• LB agar containing 50 ΅g/ml ampicillin

• LB agar containing 25 ΅g/ml tetracycline

• LB agar containing 100΅g/ml rifampicin

• MacConkey agar containing 100΅g/ml rifampicin

These plates are controls to demonstrate that the E.coli recipient is sensitive to both ampicillin and tetracycline and therefore could not grow on media containing these antibiotics unless they had received plasmids carrying ampicillin and/or tetracycline resistance genes from the F+ donor bacteria. Growth on the plates containing 100΅g/ml indicates that this organism is resistant to rifampicin.

4. Streak the creek organism onto LB agar containing 100΅g/ml rifampicin. This plate is a control to demonstrate that this organism is sensitive to rifampicin and therefore cannot grow on any plates containing 100΅g/ml rifampicin.

5. Streak the Salmonella anatum culture onto MacConkey agar containing 100΅g/ml rifampicin. This plate is a control to demonstrate that this organism is sensitive to rifampicin and therefore cannot grow on any plates containing 100΅g/ml rifampicin.

6. Incubate all plates overnight at 37oC.

DAY 4

1. Count the number of colonies on each plate and record your results using the attached table.

 

Mating Mixture or Organism

Type of Agar Plate

CFU/ml on Plate

     
     
     
     
     
     
     
     
     
     
     
     
     
     
     
     
     
     
     

 

 

COMMENTS AND QUESTIONS

1. The following controls were done to check the experimental results against the working hypothesis:

a. E.coli was streaked on

• L agar + amp

• L agar + tet

• L agar + rif

• MC + amp

• MC + tet

• MC + rif

Since this organism does not contain any plasmids carrying the genes for ampicillin or tetracycline resistance, it will not grown on agar containing either of these antibiotics. It will grow on plates containing rifampicin since it has a mutation in the RNA polymerase (chromosomal) gene which makes it resistant to the antibiotic. (Rifampicin is a semi-synthetic derivative of the antibiotic, rifamycin, produced by a strain of Streptomyces, that specifically inhibits RNA synthesis by interfering with the formation of the first phosphodiester bond in the nascent RNA chain. The site of action is the _ subunit of RNA polymerase.)

b. The creek organism was streaked on L agar + rif. Since this organism (presumably) does not have a mutation in RNA polymerase that would make it resistant to rifampicin, it should not grow on plates containing the antibiotic.

c. Salmonella anatum was streaked on MacConkey agar containing rifampicin. Since this organism does not have a mutation in RNA polymerase that would make it resistant to rifampicin, it should not grow on plates containing the antibiotic. (You may see one or two colonies growing on the +rif plates; these are spontaneous mutants in which the altered-subunit does not bind rifampicin.)

2. Why was MacConkey agar used for the S.anatum/E.coli mating? It was used to differentiate between the two bacterial species: S.anatum forms yellowish colonies while E.coli forms dark pink colonies. Do you know why?

3. Did the creek organism transfer drug resistance to the E.coli strain? Explain why you came to this conclusion.

4. Did the S.anatum transfer drug resistance to the E.coli strain? Consider the implications of this, both scientifically and from a public health standpoint. (The first time this phenomenon surfaced in the popular press was the discovery of penicillin-resistant strains of Neisseria gonococcus isolated from soldiers in or returning from Vietnam.)

D. OPTIONAL EXPERIMENTATION

Transduction

Among the phage that are best able to transfer genes from one bacterium to another is a virulent type of the temperate phage, P1, called P1vir . We shall use P1vir to infect the E.coli strain, HfrC. Recall that this strain contains the transposon, Tn10 which, in turn, contains a gene that confers resistance to the antibiotic, tetracycline, to the host. In these experiments, we will select for transduction events in which Tn10 has been transferred to the E. coli strain, AB1157, and has been incorporated into the recipient cell's chromosome. This results in a permanent alteration of the recipient cell genotype (by "natural genetic engineering") and, if we use the appropriate selection technique we can detect the resulting altered phenotype. As in the conjugation experiments, we shall do this by plating the transduction mixture on agar with different antibiotics: if we plate the mixture on agar containing tetracycline, transduced cells containing Tn10 will grow, but not the recipient strain, AB1157----but so will uninfected donor HfrC cells. Likewise, since the recipient AB1157 cells contain the gene for streptomycin resistance, plating the mixture on agar containing streptomycin will allow both transduced cells and uninfected recipient AB1157 cells to grow. But, if we plate on agar containing both antibiotics, only transduced cell that have received the Tn10 DNA will grow.

In addition to carrying the strr allele, the genome of AB1157 lacks functional genes for synthesizing five amino acids: threonine, leucine, histidine, arginine, and proline. Without these amino acids present in the growth medium, AB1157 cannot grow . The HfrC strain has wild type (i.e. functional) copies of these genes. Thus, by transducing AB1157 with P1vir phage previously grown on HfrC, some of the amino acid-synthesis genes from the HfrC may get incorporated in the AB1157 DNA. Such transduced cells can be detected by their growth in medium lacking one or more of these amino acids. (The use of two different antibiotic "markers" in the donor and recipient cells is crucial for this experimental design; do you see why?)

PROCEDURES

Preparing the P1vir phage:

Strains: An overnight culture of E. coli HfrC

An overnight culture of E. coli AB1157, a strain of Escherichia coli

P1vir phage at a titer of > 109/ml

Materials &

Equipment: L broth with 0.005 M CaCl2 (prepared by adding 0.5 ml of a sterile

1M solution of CaCl2 to 100 ml of sterile LB medium) and 0.2% glucose (prepared by adding 1 ml of sterile 20% glucose to 100 ml of sterile L broth)

L broth

R top agar (per liter: 10g Bacto-tryptone, 1g Bacto yeast extract, 8g Difco agar, 8g NaCl; after autoclaving, add 2ml of 1M CaCl2 and 3 ml of 20% glucose)

R plates (same as R top agar, except that each liter contains 12 g of agar)

chloroform

sterile tubes

ice bath

spreaders

125 ml Erlenmeyer flask

alcohol burner

37oC waterbath

Procedure:

1 Add a 0.1 ml aliquot of an overnight HfrC culture to 10 ml fresh L/Mg/glucose broth; incubate with shaking for 1 hr at 37oC.

2 Add 0.2 ml phage (to have greater than a 1:1 ratio of phage to bacteria) and shake for 2-3 hrs at 37oC.

3 Add several drops of chloroform and vortex (usually by the end of 2 hrs visible lysis has occurred and the culture goes from turbid to clear---and often cell debris is observable; but even when visible lysis hasn't occurred, high titer lysates can be obtained)

4 Centrifuge (bench top centrifuge) for at least 10 minutes at 5000 rpm, then store in refrigerator.

6 To titer:

---use a fresh overnight culture (for this experiment, we can use either the HfrC or AB1157 strain) grown in LB+CaCl2; add 0.1 ml to each of four small test tubes;

---add 0.1ml of a 10-4, a 10-6, and a 10-7 dilution of the lysate to three of the tubes (the fourth tube receives no phage, allowing of the bacterial lawn with and without P1 plaques---which are very small and hard to see).

---preadsorb the phage by incubating for 10 min at 37oC; add 2.5 ml R-top agar to each tube and plate on R plates; incubate plates overnight at 37oC

Transduction with P1vir phage:

1. Basic Observation of Gene Transfer by Transduction

a. Background

In this exercise, the antibiotics tetracycline and streptomycin will be used to select bacteria with DNA for resistance to both. (Tetracycline is used to treat penicillin-resistant strains of gonorrhea and streptomycin is used to treat acne and boils. Indiscriminate use of antibiotics will select for strains resistant to the antibiotics.) The Hfr strain (Hfr Cavelli or HfrC) used here is tetracycline resistant due to the transposon, Tn10. The genotype (with respect to the genetic markers of interest in this experiment) is: tetrstrs; phenotypically, it will grow in medium containing tetracycline, but not streptomycin. The F- strain (AB1157) has no Tn10 insert, so it is sensitive to tetracycline; however, it has a gene for streptomycin resistance at another locus, corresponding to the recessive strs allele on HfrC. The genotype is therefore: F- tetsstrr; phenotypically, it will grow in medium containing streptomycin but not containing tetracycline.

During infection of Hfr by P1vir, some of the phage heads will have packaged chunks of Hfr DNA---including those with a piece containing the tetr locus. Upon infection of AB1157 with the P1vir(Hfr) lysate, some recipient cells will be "infected" by phage containing DNA with the tetrgene; subsequent recombination will create, among other possibilities, cells carrying both the tetr allele and the strr allele. These recombinants can be selected for by plating the cell mixture on medium containing both antibiotics.

2. Materials

Strains: An overnight culture of AB1157;

P1vir (Hfr) lysate

Material &

Equipment: L agar plates with minimal salts, sodium citrate, with and without antibiotics (tetracycline and/or streptomycin)

(per liter: L agar ingredients; autoclave in 900 ml dH2O; when cool, add following sterile ingredients: 1 ml tetracycline and/or streptomycin (25 mg/ml in 50% EtOH, filter-sterilized), 100 ml 10X A salts and 5 ml 1M sodium citrate)

10X salts (per liter:105 g K2HPO4; 45 g KH2PO4; 10 g (NH4)2SO4;

5 g sodium citrate.2 H2O)

MC Buffer (0.1M MgSO4, 0.005M CaCl2)

citrate buffer (0.1M, pH 5.5: 9.6g citric acid, 4.4g NaOH, dH2O to 500ml; adjust pH to 5.5 with 10N NaOH, autoclave)

3. Procedure

1 Label plates according to chart below.

2 Spin down 2 ml of a fresh overnight culture of AB1157 and resuspend in 2 ml MC buffer.

3 Transfer 0.4 ml of the resuspended cells to each of two large sterile test tubes. To the first tube, add 0.4 ml of the phage lysate; to the second, add 0.4 ml of a 10-1 dilution of the lysate.

Controls:

Add 0.4 ml resuspended AB1157 and 0.4 ml MC buffer to a small test tube; it serves as a control for revertants of the strain tested.

To a second small test tube, add 0.4 ml of lysate with no bacteria present; this control confirms that the phage is not contaminated with bacteria.

4 Incubate tubes in 37oC water bath for 10 minutes.

5 Add 0.8 ml citrate buffer to each of the two tubes containing bacteria and phage (what do you think the purpose of this step is?). Plate 0.1 ml of each tube on duplicate sets of :

L agar (+ minimal salts + citrate) plates

L agar (+ minimal salts + citrate + tetracycline) plates

L agar (+ minimal salts + citrate + streptomycin) plates

L agar (+minimal salts + citrate + tetracycline + streptomycin) plates

Controls:

Add 0.8 ml citrate buffer to tube containing bacteria only and to the tube containing lysate only and plate 0.1 ml of each on the same set of plates. (What do each of these controls tell you?)

6 Incubate plates overnight at 37oC; count the placques and enter into the box below.

MEDIA P1vir PLAQUES (mix) CONTROL (lysate) CONTROL (cells)

L agar ______ ______ _______ _______

L agar + tet ______ ______ _______ _______

L agar + strep ______ ______ _______ _______

L agar + tet + strep ______ ______ _______ _______

 

 

2. Genomic Mapping by Generalized Transduction

a. Background

To carry out one, two, and three factor crosses require a generalized transducing phage such as P1 in E.coli, which packages almost randomly cut segments of the bacterial chromosome into phage particles and inject them into recipient strains. For the scientist, this is very useful for strain construction and for mapping within intervals smaller than two minutes. For the teacher, this is an excellent way to demonstrate how viruses can be natural vectors for genetic engineering.

Schematic diagram of the cross involving a P1 lysate prepared on the HfrC strain and the recipient strain, AB1157:

Shown below are results of a typical experiment (focusing only on the thr-1, leuB6, car region and ignoring the proA locus). Some of the classes depicted in the diagram above are represented (see if you can draw the missing recombinant classes). Note that the order of thr-1 and leuB6 determines which class of recombinants require 4 cross-overs instead of 2.

Phenotype of Tet Colonies

Number Found

Thr-Leu-

16

Thr-Leu+

40

Thr+Leu+

44

Thr+Leu-

0

 

These data allow us to draw a cotransduction map of the three markers:

The head of the arrow points to the selected marker, in this case Tet (car::Tn10). The data in the table support this order: 2 factor cross data are consistent with this order (leuB6 shows a higher contransduction frequency with car (40+44) than thr-1 does (44), and , given the expected rarity of recombinants requiring 4 cross-overs, we find no Thr+Leu- Tet recombinants.

2. Methods and Procedure

Strains: An overnight culture of AB1157

P1vir (HfrC) lysate

Materials &

Equipment: LB plates

LB plates with minimal salts, sodium citrate and tetracycline and sodium (per liter: LB ingredients; autoclave in 900 ml dH2O; when cool, add following sterile ingredients: 1 ml tetracycline (25 mg/ml in 50% EtOH, filter-sterilized), 100 ml 10X A salts and 5 ml 1M sodium citrate)

Glucose minimal plates: (test for tetr &:)

1. + tet, pro, his, arg, thr, leu

2. + tet, pro, his, arg, thr (leu+)

3. + tet, pro, his, arg, leu (thr+)

4. + tet, pro, his, arg (thr+,leu+)

5. + tet, his, arg, thr, leu (pro+)

(per liter: 100 ml 10X A salts, 12 g Difco agar; autoclave in 900 ml dH2O; when cool, add following sterile ingredients: 1 ml 1M MgSO4.7H2O, 10 ml 20% glucose, 1 ml vitamin B1 (1mg/ml), and 8 ml amino acids @ 10 mg/ml)

MC Buffer (0.1M MgSO4, 0.005M CaCl2)

sterile 0.1M sodium citrate

F-top agar (per liter: 8g NaCl; 8 g Difco agar)

10X A salts (per liter: 105 g K2HPO4; 45 g KH2PO4; 10 g (NH4)2SO4;

5 g sodium citrate.2 H2O)

Procedure:

1 Label plates according to chart below

2 Spin down 2 ml of a fresh overnight culture of AB1157 and resuspend in 2 ml MC buffer.

3 Transfer 0.8 ml of the resuspended cells to each of two large sterile test tubes. To the first tube, add 0.8 ml of the lysate made on HfrC; to the second, add 0.8 ml of a 10-1 dilution of the lysate.

Controls:

Add 0.1 ml resuspended AB1157 and 0.1 ml MC buffer to a small test tube; it serves as a control for revertants of the strain tested.

To a second small test tube, add 0.1 ml of lysate with no bacteria present; this control confirms that the phage is not contaminated with bacteria.

4 Incubate tubes in 37oC water bath for 10 minutes.

5 Add 1.6 ml 0.1M sodium citrate to each of the two tubes containing bacteria and phage. Mix by tapping tube gently and transfer 0.4 ml each transduction-sodium citrate mix to each of six small test tubes

Use one of these six tubes to plate 0.1 ml the transduction-sodium citrate mix on a LB plate and 0.1 ml on a LB+tet plate.

Add 3 ml molten F-top agar (about 50oC) to one of the remaining five tubes, swirl to mix and spread evenly (and quickly!) over a glucose minimal plate. Repeat for each type of glucose minimal plate (for both transduction mixes). Let top agar gel without disruption, about five minutes, and incubate overnight at 37oC.

Controls:

Add 0.2 ml 0.1M sodium citrate to tube containing bacteria only and plate 0.1 ml on LB and 0.1 ml on LB+tet.

Add 0.1 ml 0.1M sodium citrate to tube containing phage only and plate 0.1 ml on LB.

6 Score LB and minimal plates. (The latter may take one or two days longer to show macroscopic colonies.) Determine the co-transduction frequency and the order of the markers.

Expected results:

Plate

Hfr Lysate: 100 10-1

AB1157 only P1vir only

LB

   

LB, tet, salts, sodium citrate

 

----

glucose minimal plus:

 

---- ----

tet, pro, his, arg, thr, leu

 

---- ----

tet, pro, his, arg, thr

 

---- ----

tet, pro, his, arg, leu

 

---- ----

tet, pro, his, arg

 

---- ----

tet, his, arg, thr, leu

 

---- ----

 

 

Obseerved Results:

Plate

Hfr Lysate: 100 10-1

AB1157 only P1vir only

LB

   

LB, tet, salts, sodium citrate

 

----

glucose minimal plus:

---- ----

---- ----

tet, pro, his, arg, thr, leu

 

---- ----

tet, pro, his, arg, thr

 

---- ----

tet, pro, his, arg, leu

 

---- ----

tet, pro, his, arg

 

---- ----

tet, his, arg, thr, leu

 

---- ----

 

FOR THOUGHT AND DISCUSSION

1 What went wrong?

a) Felix mixed 25 ml of 1 X 106 cells/ml HfrC (with tetr and leu+),

25 ml of 1 X 106 cells/ml AB1157 (with tets and leu-), and

25 ml of 1 X 108 uninfected phage/ml P1vir (with no special alleles)

in a 125 ml flask and cultured the solution at 37oC for 2 hours. He predicted he would get the following numbers of colonies on serial dilutions of the product when plated on agar lacking leucine, but containing tetracycline. The data on the right is the observed densities (‘lawn’ means too many to count):

Dilution Expected count Observed count

1 300 lawn

.3 100 lawn

.1 30 lawn

.01 3 lawn

.001 0 lawn

.0001 0 129

.00001 0 9

Explain the difference between the predicted and observed results. (Assume 1 successful transduction per 1000 in ‘Expected"]

The HfrC are all growing in the medium. They already have both necessary genes.

b) Under ideal conditions, Wilhelmina incubated a solution of 25 ml 108 phage per ml P1vir that contained the tetracycline-resistant allele and the leucine-producing allele with 25 ml of 106 cells/ml AB1157 which are sensitive to tetracycline and cannot make their own leucine. She plated on agar containing the amino acids leucine, proline, and threonine an amount she expected would yield 150 colonies per plate and after two days had all plates with lawns (too many to count). Explain.

The medium has leucine in it, which is what the AB1157 needs to grow. The transduction of leucine-synthesizing alleles was not necessary; original cells grew.

c) The leucine-synthesizing allele is transferred well before the tetracycline resistant allele. Explain why you think transduction would occur more frequently or less frequently if the incubating culture is kept on a ‘shaker’. The shaker would not allow enough time for the phage to contact the bacterial surface and ?transduce? the genes.

d) If transduction is successful in the previous problem, would you expect more cells to grow on agar: a) with tetracycline, but lacking leucine, b) without tetracycline or leucine, or c) with tetracycline and leucine?

More cells can make leucine than develop tetracycline resistance, so we expect more of B. A and C should be about equal because the tetracycline is the limiting growth factor in both cases--resistance to it is transferred after the leucine allele.

2 After P1vir have grown on a strain of HfrC containing the tetr, leu+ and thr+ alleles, they are purified and mixed for a short time with AB1157 lacking all these alleles. The phenotypes of and numbers of the resultant colonies is shown below. Is the leu+ or the thr+ allele transferred first during transduction?

Phenotype of colonies Number counted .

thr- leu- 16

thr- leu+ 40

thr+ leu+ 44

thr+ leu- 0

There are more colonies with leu+ than without, so leu+ transferred first

Explain the population of ‘thr+ leu-’ being 0. Since the leu+ allele is transferred first, all colonies with thr+ would already have also received a leu+ allele; therefore, no colonies with the thr+ would exist without the leu+, too.

3 Again, after P1vir have grown the in a strain of HfrC containing the tetr, leu+, thr+, and pro+ alleles, they are purified and mixed for a short time with AB1157 lacking all but the leu+ allele. After further incubation without disturbance for 3 hours at 37oC, equal amounts of the transduced AB1157 solution are plated on five plates of each of the following media and the colonies are counted after three days. The results are shown below:

Nutrients added to the Average number of

minimal media of the agar colonies counted .

tetracycline, proline 24.4

tetracycline, threonine 3.6

tetracycline, proline, threonine 172

tetracycline 3.2

Why is tetracycline put in all media?

Only colonies of AB1157 that have received the tetracycline resistance allele from the phage will be able to grow on these media; the AB1157 that are in the solution that have not incorporated the tetr gene will die in the tetracycline-containing medium.

Comment on the relative numbers of the colonies (why are two about the same?).

The medium with proline can support all colonies with thr+ genes. The medium with threonine added can support all colonies with pro+ (and therefore also thr+) alleles. The number of these colonies is about equal to the colonies that grow on media without either the pro+ or thr+ alleles, because both colonies need to synthesize proline. The colonies growing on media with both amino acids need only built up tetracycline resistance to grow on the medium.

Explain why you believe the thr+ or pro+ allele is closer to the original gene transduced.

The pro+ if farther away. There were fewer colonies that produced there own proline because fewer of the AB1157 received that gene than received the thr+ gene.

4 A ‘U-tube’ is a tool used to study materials that diffuse across a semi-permeable membrane. Thag obtained a culture of Hfr Cavalli (HfrC, which has the F factor for conjugation) with genes for synthesis of leucine and proline. He also had a AB1157 culture which lacked genes for the amino acids’ synthesis and lacked the F factor (It was F-). He placed one of the fresh cultures on each side of the U-tube with equal amounts of the transducing phage P1vir, which can diffuse across the membrane.

 

After five hours, he made plates from the AB1157 half of the U-tube and incubated them at 37oC. After three days he counted the colonies on the plates:

 

In addition to tetracycline, Number of colonies per plate:

nutrients added to agar Plate A Plate B Plate C

proline 62 57 65

leucine 42 39 48

proline and leucine 121 111 108

 

a) The genes for which amino acid are the first to move into the recipient bacterium? leucine

b) On the diagram on the previous problem, put a mark to show where you think the gene for the synthesis of leucine is. It is to the left of the tetracycline resistance gene, but anywhere to the left of proline is correct for the information the students have.

c) Explain how and why you think the results would have been different if no phage were added to the solutions. Without phage, there would have been no way for the DNA to transfer from the HfrC to the AB1157 because the DNA is locked up in the cells and they do not move across the membrane.

d) With the phage, by what process(es) could the proline gene in HfrC get into the AB1157? There are three natural forms of recombination of DNA: Conjugation (which could occur between the F+ Hfr Cavalli and the F- AB1157), transduction (which cannot occur in the absence of the phage), and transformation (in which hereditary materials are ‘absorbed’ in the absence of a bridge or vector). Only conjugation and transformation would work in this case.

 

 

Transformation

 

 

BACKGROUND

One of the first demonstrations that DNA is the genetic material was the isolation of DNA from one strain of cells and its use to cause heritable changes in recipient cells. This phenomenon is known as transformation. In this laboratory you have the opportunity to repeat this experiment with DNA isolated from Bacillus subtilis, a common nonpathogenic soil bacterium.

Wild type B. subtilis can grow on a simple salts medium supplemented with a carbon source such as glucose. Mutants can be isolated, however, that cannot synthesize various monomers and consequently cannot grow unless the required nutrient is supplied in the medium. You are going to work with a strain (trp-) that cannot synthesize the amino acid tryptophan and show that these cells can be transformed to wild type (trp+) by incubating them with DNA from wild type B. subtilis.

The process by which recipient cells take up donor DNA still is not understood. It is facilitated by growing the recipients under specific conditions and using them just before they enter the stationary phase of growth. (It is interesting to note that RNA is not taken up by the recipient cells.) After the donor DNA enters the cell, it recombines with the chromosome to give wild type recombinants.

This is a laboratory where you will be able to design your own experiment. One of the reasons for the great interest in transformation experiments is that they allow one to correlate effects of physical or chemical alterations in the structure of DNA with its biological activity. You may want to show that the transforming principle is indeed DNA and not RNA or protein. (The DNA that you isolate from donor trp+ cells will be far from pure.) This can be done by showing that the material which gives transformants is inactivated by DNase but not by enzymes that degrade RNA or protein (RNase and pronase.) An example of the effect of some treatment on the ability of the DNA to transform recipient cells. Some possibilities are suggested below. Be sure to include appropriate controls and to show that neither the trp- recipient cells nor the DNA alone can yield colonies on plates lacking tryptophan.

Here are some ideas for things to test (each group of two can have up to 15 plates):

A. The size of the donor DNA. (It can be sheared to small pieces by squirting it rapidly through a small bore (26 gauge) syringe needle several times.)

B. Denaturing the DNA. (This can be done by heating the DNA to various temperatures then quick cooling it on ice.)

C. Non-homologous DNA added to the donor DNA. (Purified calf thymus DNA will be available.)

D. A time course of transformation. (How do you stop the reaction?)

E. Making the experiment quantitative and calculating the per cent of recipient cells transformed.

F. UV irradiation of the donor DNA. (Wear goggles to protect your eyes.) One of the effects of UV is to cause the formation of dimers between adjacent thymines in DNA.

PROCEDURE (Work in groups of two.)

A. Isolation of DNA

You will be given a tube of trp+ B. subtilis at a concentration of approximately 5x109 cells/ml. Save out a small aliquot (a few drops) to be used later so that you can show that these cells can indeed grow in the absence of tryptophan. Add 5 drops of 2 mg/ml lysozyme, and enzyme which breaks down the cell wall, mix gently, and incubate at 37oC for 10 minutes or until the solution clears. Add 6 drops of 10% (w/v) sodium dodecyl (SDS) and mix by rotating the tube at a shallow angle. SDS is a detergent which dissolves the cell membrane and denatures proteins, including enzymes which degrade DNA. The solution should become somewhat viscous due to the long, rigid DNA molecules which are released from the cells.

DNA is insoluble in most organic solvents. This property allows you to "spool out" the DNA directly from the cell lysate. Slowly and carefully layer 4 ml 100% ethanol over the cell lysate. Do not mix the two layers. (Have your lab partner hold the tube at a 45o angle on the bench top while you allow the ethanol to run slowly down the side of the tube.) Holding the tube upright, insert the etched end of a sterile glass rod through the ethanol layer and into the lysate about 1 cm below the interface. Now stir the rod in a circular motion. As the ethanol concentration in the lysate increases at the interface, the DNA will begin to form white fibers that wind around the glass rod. Continue, lowering the glass rod slowly as the ethanol into the lower phase, stopping as soon as you have a "glop" of DNA wound around your rod or when two phases are no longer visible. At this point (it should take about 5 minutes) most of the DNA, along with contaminating RNA, will be wound around the glass rod. Transfer it to 2 ml of sterile NaCl - EDTA (0.15M NaCl, 0.001M ethylene diamine tetraacetic acid- -the EDTA protects the DNA from any DNase that might still be around by chelating Mg++ which is required for DNase to act) and shake gently. Notice that the DNA swells on the rod and becomes transparent. It will take about 10 minutes to dissolve the DNA. If you have a lot of DNA, not all of it will dissolve; that is all right.

B. Treatment of DNA

Dilute your DNA 1:10 in sterile saline (0.15M NaCl.) For most experiments, 2.0ml of diluted DNA is plenty. Treat samples of this diluted DNA according to the experiment that you have planned, and the mix 0.1ml of each with recipient cells as described below. Be sure to include a tube containing untreated DNA as well.

C. Transformation

1. You will be provided with 2.0ml of 10-fold concentrated recipient cells in a tiny tube on ice. Add 0.8ml of Medium II and transfer the entire 1.0 ml to a small sterile test tube with a Pasteur pipette.

2. Set up a series of small test tubes according to the experiment you have planned. Use 0.1ml of DNA where desired, 1 drop of enzyme (if your experiment calls for this), and 0.1 ml of diluted recipient cells (or Medium II in the case of controls lacking recipient cells.) Recipient cells should be added last when all other components are ready. Vortex the tubes and incubate at 37oC for 15 minutes or under the conditions that you have chosen.

3. Plate out the cells after the incubation period by pouring or pipetting the contents of each tube onto numbered plates of salts - glucose - agar medium with or without tryptophan. Dip a glass spreader into ethanol and flame it to sterilize it. (Be careful that you do not flame yourself!) Allow a few seconds for cooling. Spread the liquid across the surface of the agar while rotating the plate.

4. Incubate your plates for a day at 37oC and then count the colonies (piles of cells derived from a single cell) on them to determine your results. If there are a large number of colonies on a plate (more that a couple hundred), you may wish to estimate the number or simply write down "too many to count." Note that putting a very large number of cells on a plate will result, the next day, in a "lawn" of growth rather than individual colonies. Discard your plates after you have noted your results.

RESULTS AND DISCUSSION

Explain your results, the controls you used, and the purpose of each. What can you say about the properties of DNA that are necessary for it to be biologically active in transformation? How could the experiment be refined to the point where you could be certain that DNA and not some trace material is the transforming principle?

NOTES

Medium II (Similar to the medium in which the cells were

0.15 M NH4Cl grown, but lacking amino acids and glucose) 0.08 M K2HPO4

0.4 M KH2PO4

0.003 M Na citrate

0.002 M MgCl2 6H2O

APPENDIX

Example of a protocol to test whether the transforming principle is DNA.

Volumes are in ml.

Tube No.

1:10 DNA

DNase

RNase

Pronase

Recp. Cells

Results

1.

       

0.1

 

2.

0.1

     

 

3.

0.1

     

0.1

 

4.

0.1

1 drop

   

0.1

 

5.

0.1

 

1 drop

 

0.1

 

6.

0.1

   

1 drop

0.1

 

The above mixtures should be put onto plates lacking tryptophan. In addition, you probably will want to put a sample of donor cells onto plates lacking tryptophan and samples of donor and recipient cells onto plates containing tryptophan.